X^2+36x-460=0

Solution for X^2+36x-460=0 equation:

X^2+36X-460=0

a = 1; b = 36; c = -460;
Δ = b2-4ac
Δ = 362-4·1·(-460)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-56}{2*1}=\frac{-92}{2}
=-46
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+56}{2*1}=\frac{20}{2}
=10
$